Base Plates and Anchor Rods
Column base plate design and anchor rod sizing (AISC Design Guide 1).
- AISC 360-22 §J8 — Column Bases and Concrete Bearing
- AISC Design Guide 1 — Base Plate and Anchor Rod Design
Lecture Notes
This module introduces base plates and anchor rods. Lecture content here covers the governing physics, LRFD philosophy, and how the relevant AISC 360-22 chapter organizes the limit states.
Instructors can replace this text in Admin Mode. Each section is structured around: (1) behavior, (2) failure modes, (3) AISC limit-state equations, (4) design workflow, (5) detailing requirements.
A short comparison to ASD is included only where the resistance factor / safety factor relationship clarifies the LRFD design check.
Every chapter's worked example is one step in the design of the same building: Plan: 4 bays N–S × 3 bays E–W, each 30 ft × 30 ft. Stories: 4 @ 13 ft (52 ft roof). Composite floor: 4.5 in NW concrete on 3 VLI20 deck. Roof: 1.5 in B-deck + insulation + membrane. Materials: Wide-flange members A992 (Fy = 50 ksi, Fu = 65 ksi). Plates A572 Gr. 50. HSS bracing A500 Gr. C. Bolts A325-N 7/8 in dia. Welds E70XX. Concrete f'c = 4 ksi. Anchor rods F1554 Gr. 36.
Formula Sheet
| Name | Equation | AISC Ref |
|---|---|---|
| Concrete bearing | φc Pp = 0.65 · 0.85 · fc' · A1 · √(A2/A1) ≤ 0.65 · 1.7 · fc' · A1 | AISC §J8 |
Worked Example
Base Plates and Anchor Rods
- Limit state 1
- Limit state 2
- 1. Required strengthCompute Ru.
- 2. Trial sectionPick a trial from AISC shape tables Instructor should verify with official AISC Manual.
- 3. Check each limit stateApply φ Rn ≥ Ru for every governing limit state.
- 4. IterateResize until the most economical section satisfies all checks.
- Skipping a limit state
- Using the wrong φ factor
- Forgetting serviceability checks
FE-Style Worked Examples (6)
Each example mirrors the NCEES FE Civil Reference Handbook style: brief givens, a labeled figure, AISC section reference, step-by-step numeric solution, and a single boxed answer.
- √(A2/A1)√(576/256) = 1.5 ≤ 2 ✓
- φPp0.65 × 0.85 × 4 × 256 × 1.5 = 849 k (≤ 0.65×1.7×4×256 = 1131 k) → use 849 k
Textbook — Aghayere & Vigil (2009)(3 worked examples with figures + numerical answers)
Worked examples scanned directly from the CEGR 436 course textbook. Each card shows the original page (figure + full step-by-step solution) and adds an FE-style numerical multiple-choice prompt with answer key.
Chapter 8 §8.13–§8.18 of the textbook covers base plate and anchor rod design (AISC Design Guide 1). The plate transfers column axial load and moment into the pier via bearing; anchor rods carry uplift and shear from wind/seismic.
- Concrete bearing: φcPp = 0.65·0.85·fc'·A1·√(A2/A1) ≤ 0.65·1.7·fc'·A1 (AISC §J8).
- Plate thickness for axial load: tmin = ℓ·√(2·Pu/(0.9·Fy·BN)) per DG1.
- Anchor rods: shear via friction + bearing on rod, or use shear lugs (DG1 §3.5).
- Uplift: rod tension capacity = 0.75·Fnt·Ab per AISC §J3.6.
- Always check the leveling-plate / grout pad thickness (≥ 1 in typical).

Interactive Calculator
Base Plate Concrete Bearing
AISC §J8Practice Problems
- [E] State φc = 0.65 for concrete bearing.
- [E] State φc·Pp = 0.65·0.85·f'c·A1·√(A2/A1).
- [E] Sketch base plate showing N x B dimensions.
- [E] List four anchor-rod ASTM specs (F1554 Gr 36, 55, 105; A36).
- [E] State cantilever lever-arm distances m and n.
- [M] Size base plate for Pu = 400 k, W12x72, f'c = 4 ksi, A2/A1 = 4.
- [M] Required plate thickness using cantilever method (above).
- [M] Anchor-rod design for 50 k uplift (Combo 6) at a 16 x 16 in. base plate.
- [M] Shear-key design for Vu = 20 k at an interior column base.
- [M] Anchor-rod pull-out check per ACI 318 Appendix D for two 1 in. F1554 Gr 55 rods.
- [H] Full base plate: Pu = 800 k + Mu = 60 k-ft, W14x90, f'c = 4 ksi, A2/A1 = 2.25.
- [H] Base plate under axial + uplift + shear: plate thickness, anchor rods, shear key.
- [H] 30 x 30 in. concrete pier with 4 #8 verticals: check concrete breakout per ACI 318-19 Ch. 17.
- [H] Large-e base plate (e > N/6): bearing area + anchor-rod tension per DG-1 Method 2.
- [H] Portal-frame base: design for Mu = 250 k-ft, Pu = 220 k with leveling nuts.
Quiz
Common Student Mistakes
- Mixing ASD and LRFD load combinations in the same problem.
- Using nominal strength Rn instead of design strength φRn.
- Forgetting to check every limit state listed in the AISC chapter.
"Professor Explains" Script
Today we're talking about base plates and anchor rods. Think of this topic as one step in the LRFD workflow: identify the demand, identify the limit states from the relevant AISC chapter, then check that φ·Rn is at least equal to Ru. We'll walk through the failure modes, the equations, and a worked example. Pay close attention to where the resistance factor changes — that's where students lose points on exams.