Beam-column design with second-order effects, B1/B2 factors.
A real project narrative for this chapter will be authored as this chapter migrates to the v3.0 structured schema.
Beam-column design with second-order effects, B1/B2 factors.

Beam-column design with second-order effects, B1/B2 factors.
A real project narrative for this chapter will be authored as this chapter migrates to the v3.0 structured schema.
Photographs and lessons-learned case studies for this topic will be added during chapter migration.
Sway frames experience P-Δ (structure-level) and P-δ (member-level) second-order effects. Ignoring these gives moments that can be 20–50% too low, leading to premature buckling.
Foundational for Chapter 17 stability and every moment-resisting column in Chapters 19–20.
Use this reference to flip directly to the correct page of the AISC 360-22 Specification while solving problems in this course chapter.
| § | Section title | Page |
|---|---|---|
| C1 | General Stability Requirements | 16.1-15 |
| C2 | Calculation of Required Strengths (Direct Analysis Method) | 16.1-16 |
| C3 | Calculation of Available Strengths | 16.1-19 |
| H1-1a | Interaction Eq. (Pr/Pc ≥ 0.2) | 16.1-114 |
| H1-1b | Interaction Eq. (Pr/Pc < 0.2) | 16.1-114 |
| App. 8 | Approximate Second-Order Analysis (B1, B2 Amplifiers) | 16.1-235 |
Companion reference: AISC Manual Part 6 & Appendix 8
Skip the amplification math if you can — but only when the code lets you. AISC 360-22 §C1.3 permits a first-order analysis (no B1/B2, no DAM) only when both of these hold at every story:
Where RM = 1.0 (braced) or 0.85 (moment frames), H is the story shear producing story drift ΔH, and L is the story height.
Subscripts: nt = "no-translation" (gravity analysis with joints held), lt = "lateral-translation" (sway analysis).
Instead of B1/B2, run a rigorous second-order analysis with reduced stiffness (0.8·τb·EI, 0.8·EA), notional loads Ni = 0.002·α·Yi, and K = 1.0 in the member check.
Companion reference: Manual Part 6 (Table 6-2) + Appendix 8 / Chapter C (B1/B2 amplifiers). In practice, engineers rarely compute every quantity from first principles — the AISC Steel Construction Manual (16th Ed.) tabulates φRn (or Rn/Ω) for every rolled shape so you can pick a member in seconds. Formulas remain essential for understanding, verifying, and for anything the tables do not cover.
The Manual tables assume K=1.0 (Direct Analysis Method) and require you to enter amplified Mr = B1·Mnt + B2·Mlt. Compute B1, B2 by hand (Chapter C), then use Table 6-2 exactly as for the H1.1 check above.
Common shortcut: if the frame is braced and reverse-curvature (Cm ≤ 0.6, α Pr/Pe1 < 0.05), B1=1.0 exactly and no amplification is required — go straight to Table 6-2.
Every chapter's worked example is one step in the design of the same building: Plan: 4 bays N–S × 3 bays E–W, each 30 ft × 30 ft. Stories: 4 @ 13 ft (52 ft roof). Composite floor: 4.5 in NW concrete on 3 VLI20 deck. Roof: 1.5 in B-deck + insulation + membrane. Materials: Wide-flange members A992 (Fy = 50 ksi, Fu = 65 ksi). Plates A572 Gr. 50. HSS bracing A500 Gr. C. Bolts A325-N 7/8 in dia. Welds E70XX. Concrete f'c = 4 ksi. Anchor rods F1554 Gr. 36.
| Name | Equation | AISC Ref |
|---|---|---|
| Interaction (Pr/Pc ≥ 0.2) | Pr/Pc + (8/9)(Mrx/Mcx + Mry/Mcy) ≤ 1.0 | AISC §H1.1(a) |
| Interaction (Pr/Pc < 0.2) | Pr/(2 Pc) + (Mrx/Mcx + Mry/Mcy) ≤ 1.0 | AISC §H1.1(b) |
Chapter 8 of the textbook develops beam-column design. AISC §H1 interaction equations combine the axial demand ratio Pr/Pc with bending demand ratios Mrx/Mcx, Mry/Mcy. Second-order effects use B1 (no-translation) and B2 (translation) amplifiers per Appendix 8, or solve via the Direct Analysis Method (Chapter C).
Setup. W12×72, A992, Pu = 400 k, Mux = 200 k·ft, Muy = 0. φcPn = 818 k, φbMnx = 425 k·ft.
AISC Reference: AISC §H1.1
Interaction ratio?
Pr/Pc = 400/818 = 0.489 ≥ 0.2 → H1-1a: 0.489 + (8/9)(200/425) = 0.489 + 0.418 = 0.91 ≤ 1.0 OK.
Setup. Single-curvature: M1 = +60 k·ft, M2 = +120 k·ft; Pu = 250 k; Pe1 = 2400 k.
AISC Reference: AISC App. 8
B1?
Cm = 0.6 − 0.4·(60/120) = 0.4. B1 = 0.4/(1 − 1.0·250/2400) = 0.4/0.896 = 0.446 < 1 → use B1 = 1.0; for opposite-curvature inputs (M1/M2 = −0.5) Cm = 0.8 → B1 = 0.893/0.896 ≈ 1.05.
Setup. Story gravity ΣPnt = 1800 k; story buckling sum ΣPe2 = 12,000 k; α = 1.0 (LRFD).
AISC Reference: AISC App. 8
B2?
B2 = 1/(1 − 1.0·1800/12000) = 1/0.85 = 1.176.
Each example mirrors the NCEES FE Civil Reference Handbook style: brief givens, a labeled figure, AISC section reference, step-by-step numeric solution, and a single boxed answer.

These questions reference AISC Steel Construction Manual (16th ed.) — sections, equations, and tables are cited explicitly. Use a calculator. Each question offers a clue you may reveal before answering. Submissions are recorded to your account once signed in.
Attach your handwritten or typed step-by-step solution for this chapter's graded quiz. The instructor can download every submission. PDF only, up to 25 MB.
Your file — PDF, Word document, scanned handwriting or a photo — is read page by page like an experienced structural engineering instructor would. The scan is validated first, then your reasoning, structural model, calculations, diagrams, code basis and final answers are graded on process, not just the final number. Design work is additionally reviewed against AISC 360-22 and ACI 318-19. Partial credit applies, and one early mistake carried correctly forward is only penalized once.
Calculator tips coming soon.
Traps coming soon.
Aim for ~3 minutes per FE problem; skip and return to any item that takes longer than 5 minutes.