Bolt shear, bearing, tearout, slip-critical (Chapter J).
A real project narrative for this chapter will be authored as this chapter migrates to the v3.0 structured schema.
Bolt shear, bearing, tearout, slip-critical (Chapter J).

Bolt shear, bearing, tearout, slip-critical (Chapter J).
A real project narrative for this chapter will be authored as this chapter migrates to the v3.0 structured schema.
Photographs and lessons-learned case studies for this topic will be added during chapter migration.
Connections transfer forces between members. The Hyatt Regency (1981) and countless smaller failures traced back to bolt shear, bearing, tearout, or slip-critical assumptions that the designer got wrong.
Every bolted joint in Chapters 14 (shear), 15 (moment), 16 (base plates), 19 (framing), and the capstone.
Use this reference to flip directly to the correct page of the AISC 360-22 Specification while solving problems in this course chapter.
| § | Section title | Page |
|---|---|---|
| J3.1 | High-Strength Bolts (A325, A490, F3125) | 16.1-127 |
| J3.3 | Minimum Spacing | 16.1-129 |
| J3.4 | Minimum Edge Distance (Table J3.4) | 16.1-130 |
| J3.6 | Tensile and Shear Strength of Bolts | 16.1-131 |
| J3.7 | Combined Tension and Shear in Bearing-Type | 16.1-133 |
| J3.8 | Slip-Critical Connections | 16.1-133 |
| J3.10 | Bearing and Tearout at Bolt Holes | 16.1-136 |
Companion reference: AISC Manual Part 7 — Design Considerations for Bolts
Structural failures overwhelmingly begin at connections, not at midspan. Three reasons:
This is why AISC assigns rupture-mode resistance factors (φ = 0.75) that are stingier than member yielding (φ = 0.90), and why the entire philosophy of connection design is to make the ductile mode govern where possible.
AISC 360-22 organizes high-strength bolts by strength group rather than by the historical A325/A490 designations. All are covered by ASTM F3125/F3125M.
Read the "N" and "X" carefully. N means threads are iNcluded in the shear plane; X means eXcluded. The 26% difference between 54 and 68 ksi is entirely about whether the shear plane cuts the threaded root area or the full shank. In practice, always assume N unless you can guarantee the geometry — a shop that substitutes a longer bolt will put threads back in the plane and you will never know.
Ab = πdb²/4 is the nominal shank area — always, even for thread condition N. The thread reduction is already baked into the lower Fnv value, so never reduce Ab as well (a classic double-count).
Multiply Rn by the number of shear planes the bolt crosses. A lap splice (two plies) → 1 plane. A butt/double-lap splice (three plies) → 2 planes. A double-angle framing connection → the web bolts are in double shear, the support bolts are usually single shear. Getting this wrong is a factor-of-two error, and it is the single most common student mistake in this chapter.
In connections longer than 38 in. between extreme fasteners in the line of force, the end bolts pick up more load than the interior ones (shear lag in the fastener group). The Specification's Fnv values already contain a modest reduction for this; for very long splices, refer to the Commentary.
These two modes describe the plate, not the bolt, and they are checked at every bolt individually because each bolt has a different clear distance.
"Deformation at the bolt hole at service load is a design consideration" means you care whether the hole ovalizes by more than about ¼ in. For nearly all building work the answer is yes, so use the 2.4/1.2 forms. The 3.0/1.5 forms apply only where hole elongation genuinely does not matter (e.g. a redundant, non-architectural, non-fatigue connection).
At each bolt, the plate strength is the lesser of bearing and tearout. Then the bolt's contribution to the joint is the lesser of that plate value and the bolt shear value — this "effective strength per bolt" logic is stated in the User Note to §J3.7 and is exactly how AISC Manual Part 10 builds its tables.
Where a bolt loads a flexible flange or plate (hanger connections, tee stubs, end-plate moment connections), the fitting bends and bears back on the bolt at its toe. This prying action adds a force q to the applied tension:
Prying can add 20–60% to the bolt force in a thin fitting. The design cure is thickness: a fitting thick enough that it does not bend has no prying. AISC Manual Part 9 gives the closed-form tmin to eliminate prying entirely.
A bolt resisting both tension and shear has a reduced tensile strength. AISC uses a straight-line clip of the true elliptical interaction:
where frv = required shear stress = Vr/Ab. Exemption: per the User Note, the interaction may be ignored if either the required shear stress or the required tensile stress is ≤ 30% of the corresponding available stress. Note that the equation reduces the tensile capacity; the Commentary gives the mirror form if you prefer to reduce shear instead.
Resistance factors depend on hole type — this is where slip-critical design bites:
Applied tension partially un-clamps the joint, so there is less normal force available to generate friction. The nominal slip resistance is multiplied by ksc:
Tu and Ta are the total tension on the bolt group and nb is the number of bolts carrying that tension — the per-bolt division is already inside the formula. Omitting ksc is the most common slip-critical design error, and Worked Example 12.5 shows a case where including it moves the joint from 71% to 99% utilization.
Note that spacing and edge distance are not merely detailing rules — they feed directly into lc, and hence into tearout strength. Tightening an edge distance to save an inch of plate can cost you 25% of the connection.
Ubs = 1.0 when tension stress is uniform (most gusset plates, angles, coped beams); Ubs = 0.5 when it is non-uniform (e.g. a coped beam with two bolt lines). In net-area calculations, remember §B4.3b: add ⅟₁₆ in. to the hole diameter to allow for damage from punching, so a ¾ in. bolt in a standard hole removes ⅞ in. of material.
Companion reference: Manual Part 7 — Tables 7-1 (φrn shear), 7-2 (tension), 7-4/7-5 (slip-critical), 7-6 (bearing & tearout), 7-11 (eccentric bolt groups). In practice, engineers rarely compute every quantity from first principles — the AISC Steel Construction Manual (16th Ed.) tabulates φRn (or Rn/Ω) for every rolled shape so you can pick a member in seconds. Formulas remain essential for understanding, verifying, and for anything the tables do not cover.
Example — 6 bolts, 3/4″ A325-N, single shear, 1/2″ ply: Table 7-1 → φrn = 17.9 kip/bolt; Table 7-6 → bearing 39.2 kip/in × 0.5″ = 19.6 kip, tearout 40.8 × 0.5 = 20.4 kip. Bolt shear governs → φRn = 6 × 17.9 = 107 kip. Two look-ups, done.
Every chapter's worked example is one step in the design of the same building: Plan: 4 bays N–S × 3 bays E–W, each 30 ft × 30 ft. Stories: 4 @ 13 ft (52 ft roof). Composite floor: 4.5 in NW concrete on 3 VLI20 deck. Roof: 1.5 in B-deck + insulation + membrane. Materials: Wide-flange members A992 (Fy = 50 ksi, Fu = 65 ksi). Plates A572 Gr. 50. HSS bracing A500 Gr. C. Bolts A325-N 7/8 in dia. Welds E70XX. Concrete f'c = 4 ksi. Anchor rods F1554 Gr. 36.
| Name | Equation | AISC Ref |
|---|---|---|
| Bolt shear | φRn = 0.75 · Fnv · Ab | AISC §J3.7 |
| Bearing | φRn = 0.75 · 2.4 · db · t · Fu | AISC §J3.11 |
| Tearout | φRn = 0.75 · 1.5 · lc · t · Fu | AISC §J3.11 |
Problem statement. A tension splice joins two ½ in. thick ASTM A572 Grade 50 plates (Fy = 50 ksi, Fu = 65 ksi) in a single-shear lap with four ¾ in. diameter Group 120 (A325) bolts in standard holes, thread condition N. Bolts are in two rows of two, with edge distance le = 1.5 in. in the direction of force and spacing s = 3.0 in. Determine the available strength of the bolt group considering bolt shear, bearing and tearout. Deformation at the bolt hole at service load is a design consideration.
Engineering interpretation: shear governs because the plate is thick relative to the bolt (t = 0.5 in. of 65 ksi steel is stronger in bearing than the 54 ksi bolt is in shear). Flip that around — a ¼ in. plate — and bearing/tearout would govern instead. Also note the edge bolt is only 1.8× stronger in tearout than the bolt is in shear; shortening le to 1¼ in. would drop tearout to 26.7 kips and it would still not govern, but at 1 in. it would. This is why AISC Table J3.4 minimum edge distances exist.
Adapted from AISC Design Examples V16.0, Example J.3
Problem statement. A ¾ in. diameter Group 120 bolt with threads not excluded from the shear plane (condition N) is subjected to a tension force of 3.5 kips dead load + 12 kips live load, and a shear force of 1.33 kips dead + 4 kips live. Check the combined stresses using AISC Specification Equations J3-3a/J3-3b.
Engineering interpretation: the shear present here costs the bolt 14% of its tensile capacity (29.8 → 25.5 kips). The Eq. J3-3a form is a straight-line clip of the true elliptical interaction, and the 1.3 coefficient is what makes the straight line tangent to that ellipse. Practically: if a bolt is doing two jobs, size it for the pair, not for each job separately.
Adapted from AISC Design Examples V16.0, Example J.4A
Problem statement. A double-lap splice (two slip planes) must carry PD = 17 kips and PL = 51 kips. The connection plates have short slots transverse to the direction of load, no fillers, Class A faying surfaces, and washers per RCSC Specification Section 6. Using ¾ in. Group 120 bolts, determine the number of bolts required for slip resistance only.
Engineering interpretation: slip resistance is a serviceability-flavoured strength check: it prevents the connection from ratcheting into bearing. Because it is friction, it scales with pretension Tb, not with bolt shear area — which is why doubling bolt diameter does not double slip resistance the way it does bolt shear. Note also that ns = 2 doubles the answer: a double-lap joint is dramatically more slip-efficient than a single lap.
Adapted from AISC Design Examples V16.0, Example J.4B
Problem statement. Repeat Example 12.3 with the same loads, but with long-slotted holes parallel to the direction of load.
Engineering interpretation: hole type is not a detailing afterthought — it is a strength decision that can cost you 33% more bolts. Long slots buy erection tolerance; the code charges for it. If the fabricator asks for long slots late in the job, that request has to come back through the engineer, because the connection was almost certainly designed for standard holes.
Adapted from AISC Design Examples V16.0, Example J.5
Problem statement. The slip-critical bolt group shown has 8 bolts, ¾ in. diameter, Group 120, standard holes, Class A surfaces, one slip plane per bolt. An inclined brace delivers PD = 15 kips and PL = 45 kips along a 3-4-5 slope, so the connection sees both tension and shear. Determine whether the bolts are adequate for tension and for slip.
Engineering interpretation: this example is the whole point of §J3.10. Ignore ksc and the connection looks 71% utilized and comfortable; include it and it is at 99.4%. The physics is direct — externally applied tension partially un-clamps the joint, so there is less normal force available to generate friction. Notice that bolt tension rupture is nowhere near critical (0.301). In slip-critical joints with axial tension, slip almost always governs long before bolt strength does.
Chapter 9 develops bolt mechanics. A bolt may fail in (a) shear of the bolt body, (b) bearing of the plate against the bolt, (c) tearout of plate material to the edge, (d) tension of the bolt body, or (e) slip in a slip-critical joint. AISC §J3 governs.
Setup. 3/4" A325-N bolt (Fnv = 54 ksi, Ab = 0.442 in²) in single shear.
AISC Reference: AISC §J3.7
φrn per bolt?
φrn = 0.75·54·0.442 = 17.9 k.
Setup. 6 bolts (3/4" A325-N) in double shear connecting a tension splice.
AISC Reference: AISC §J3.7
Total φRn?
Per bolt double shear = 2·17.9 = 35.8 k; 6·35.8 = 215 k.
Setup. 3/4" bolt through PL 3/8", A36 (Fu = 58 ksi), 3-in spacing, 1.5-in edge.
AISC Reference: AISC §J3.11
φRn (bearing, deformation OK)?
φRn = 0.75·2.4·0.75·0.375·58 = 29.4 k. (Tearout is also OK: lc = 1.5 − 0.5·(13/16) = 1.09 in; φRn,t = 0.75·1.5·1.09·0.375·58 = 26.7 k → tearout governs ≈ 27 k; pick bearing/tearout min.)
Setup. Vertical bracket bolted with 6 bolts (3 rows × 2 cols) at 3-in spacing, load P at 6-in eccentricity.
AISC Reference: AISC Manual Table 7-7
Direct shear component per bolt (P = 60 k)?
rv = P/n = 60/6 = 10 k. Add torsional rt,x and rt,y components vectorially to find resultant.
Setup. 3/4" A325 SC, Class A surface, single shear, Tb = 28 k pretension, single slip plane.
AISC Reference: AISC §J3.8
φRn (slip)?
φRn = 1.0·0.30·1.0·1.0·28·1 = 8.4 k per bolt (Class A).
Each example mirrors the NCEES FE Civil Reference Handbook style: brief givens, a labeled figure, AISC section reference, step-by-step numeric solution, and a single boxed answer.

These questions reference AISC Steel Construction Manual (16th ed.) — sections, equations, and tables are cited explicitly. Use a calculator. Each question offers a clue you may reveal before answering. Submissions are recorded to your account once signed in.
Attach your handwritten or typed step-by-step solution for this chapter's graded quiz. The instructor can download every submission. PDF only, up to 25 MB.
Your file — PDF, Word document, scanned handwriting or a photo — is read page by page like an experienced structural engineering instructor would. The scan is validated first, then your reasoning, structural model, calculations, diagrams, code basis and final answers are graded on process, not just the final number. Design work is additionally reviewed against AISC 360-22 and ACI 318-19. Partial credit applies, and one early mistake carried correctly forward is only penalized once.
Calculator tips coming soon.
Traps coming soon.
Aim for ~3 minutes per FE problem; skip and return to any item that takes longer than 5 minutes.