Exam Simulator
20 randomized questions drawn from a pool of 205 (120 steel · 77 concrete · 8 general). Every new attempt reshuffles.
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- 1As,min for flexure (ACI §9.6.1.2):concrete · RC Flexure
- 2Modulus of rupture fr = 7.5λ√f'c for f'c = 4000 psi, NWC:concrete · RC Materials
- 3Which AISC 360-22 chapter primarily governs capstone design project?steel · Capstone Design Project
- 4The basic LRFD design inequality is:steel · LRFD
- 5Minimum longitudinal reinforcement ratio ρg for columns:concrete · RC Columns
- 6β1 for f'c = 4000 psi:concrete · RC Flexure
- 7λ for lightweight concrete (typical):concrete · RC Materials
- 8FEXX = 70 ksi for E70 electrodes gives strength per inch (w = 1/4):steel · Welds
- 9Cv1 for h/tw ≤ 2.24√(E/Fy) equals:steel · Shear
- 10Fixed–free (flagpole) recommended K =steel · Compression
- 11Shear stud strength is governed by:steel · Composite
- 12In LRFD, the basic design inequality is:steel · Steel Framing Systems
- 13ASCE 7 load combination 1.2D + 1.6L + 0.5(Lr or S or R) corresponds to:steel · LRFD
- 14Concrete shear strength Vc (simplified, NWC) =concrete · RC Shear
- 15Effective flange width of a T-beam (interior, ACI §6.3.2):concrete · RC Flexure
- 16Pinned–pinned column, recommended K =steel · Compression
- 17Compute a (in.) for As = 2.0 in², fy = 60 ksi, f'c = 4 ksi, b = 12 in.:concrete · RC — Flexural Design of Beams
- 18A flexural section is tension-controlled (φ = 0.90) when:concrete · RC — Flexural Design of Beams
- 19Complete-joint-penetration (CJP) groove weld strength equals:steel · Welds
- 20Vu = wL/2 for a uniformly loaded simple beam where w =steel · Shear